Question

Find zeros of polynomial p(x)=x³-9x​

Answer 1

Step-by-step explanation:

1/3 is the

zeros of polynomial p(x)=x³-9x

Answer 2

Answer:

PLZ MAKE ME BRILLIANT

Step-by-step explanation:

For finding zeroes of a polynomial p(x), put p(x) = 0.

Let p(x) = x 3 + 5x 2 – 9x – 45 and  q(x) = x 3 + 8x 2 + 15x.

p(x) = x 3 + 5x 2 – 9x – 45 = 0

x 2 (x + 5) – 9(x + 5) = 0

(x + 5) (x 2 – 9) = 0

(using identity: (a 2 – b 2 ) = (a + b)(a - b))

(x + 5) (x + 3) (x – 3) = 0Now, the different values are,(x + 5) = 0, x = -5(x + 3) = 0, x = -3(x - 3) = 0, x = 3

∴ On putting p(x) = 0, we get x = -5, x = -3, x = 3 as its zeroes.

 q(x) = x 3 + 8x 2 + 15x = 0

x (x 2 + 8x + 15) = 0

x (x 2 + 5x + 3x + 15) = 0

x (x(x + 5)+ 3(x + 5)) = 0

x (x + 5) (x + 3) = 0

Different values are,x = 0(x + 5) = 0, x = -5(x + 3) = 0, x = -3 ∴ On putting q(x) = 0, we get x = 0, x = -5, x = -3 as its zeroes.