Question

find zeros of polynomial X^2_5 answer​

Answer 1

Answer:

Given polynomial is x^2-5

Let the zeros be α,β. (α>β)

x^2-5=0 => x^2=5 or x = ✓+-5

or alpha = +√5 and beta =-√5

so alpha+beta =0 and alpha×beta=-5

So, α+β=0,αβ=−5

The coefficient of x is zero ⇒α+β=0

(& of x 2 is 1).

Constant = αβ=−5

Hence verified.

Step-by-step explanation:

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