Question

Find zeros of polynomial x^2+8/3+21/8​

Answer 1

Step-by-step explanation:

Given polynomial is P(x)=x2-2x-8

Given polynomial is P(x)=x2-2x-8Take P(x)=0

Given polynomial is P(x)=x2-2x-8Take P(x)=0x2-2x-8=0

Given polynomial is P(x)=x2-2x-8Take P(x)=0x2-2x-8=0x2-4x+2x-8=0

Given polynomial is P(x)=x2-2x-8Take P(x)=0x2-2x-8=0x2-4x+2x-8=0x(x-4)+2(x-4)=0

Given polynomial is P(x)=x2-2x-8Take P(x)=0x2-2x-8=0x2-4x+2x-8=0x(x-4)+2(x-4)=0(x-4)(x+2)=0

Given polynomial is P(x)=x2-2x-8Take P(x)=0x2-2x-8=0x2-4x+2x-8=0x(x-4)+2(x-4)=0(x-4)(x+2)=0x=4 or x=-2

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