Question

. Find zeros of polynomial x2 +7x+10 and verify relationship between zeros and the coefficient

Answer 1

Step-by-step explanation:

x2 +7x+10

using middle term splitting

x2 +5x+2x+10

X(X+5)+2(X+5)

(X+2) (X+5)

X= -2,-5

Sum of zeroes : (-2)+(-5)= -7 = -(coefficient of X)÷ coefficient of x2= -7/1= -7

product of zeroes:(-2)×(-5)=10= constant term÷coefficient of x2= 10/1=10

hence LHS=RHS