Find zeros of polynomial x2-7x+6.
Answers
Answered by
11
x2 - 7x + 6
= x² - 6x - x + 6
= x(x-6) -1 (x-6)
= (x - 1) (x -6)
x = 1 and x = 6
Thanks
= x² - 6x - x + 6
= x(x-6) -1 (x-6)
= (x - 1) (x -6)
x = 1 and x = 6
Thanks
Anonymous:
zeros will be 1 and 6
Answered by
19
Now, x² - 7x + 6
= x² - (1 + 6)x + 6
= x² - x - 6x + 6
= x (x - 1) - 6 (x - 1)
= (x - 1) (x - 6),
which is the required factorization.
Thus, the zeroes of the given polynomial are 1 and 6.
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