Question

find zeros of polynominal (x-2)whole square+4

Answer 1

(x-2)²+4=0
x²-2×2x+4+4=0
x²-4x+8=0
x=-(-4)+-√16-32/2
x=4+-√-16/2
x=4+-√16i/2. where i=√-1
x=4+-4i/2
x=2(2+-2i)/2
x=2+2i and x=2-2i

where i is a imaginary no.