Question

find zeros of q. p. 5tsquare+12t+7. verify the relationship between zeroes and coefficients

Answer 1

5t²+12t+7
a×b=5×7=35
Sum=12
And 5+7=12
•5t²+5t+7t+7=0
•5t(t+1)+7(t+1)=0
•(5t+7)(t+1)=0
So 5t+7=0 or t+1=0
•t1=-7/5 or t2=-1
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relationship
t1×12=c/a
And
t1+t2=-b/a
t1×t2=-7/5×-1=7/5
t1+t2=-7/5+-1=-(-12)/5