find zeros of quadratic polynomial 5 x square - 4 - 8 x and verify the relationship between its zeros and the coefficients
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Hi !
5x² - 4 - 8x is written in standard form as:-
p(x) = 5x² - 8x - 4
a = 5 , b = -8 , c = -4
sum of zeros = -b/a = -(-8)/5 = 8/5
product of zeros = c/a = -4/5
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5x² - 8x - 4 = 0
5x² - 10x + 2x - 4 = 0
5x(x - 2) + 2(x - 2) = 0
( x - 2) ( 5x + 2) = 0
x = 2
x = -2/5
The zeros are 2 and -2/5
sum of zeros = 2 + -2/5 = 10 -2/5 = 8/5 = -b/a
product of zeros = 2 × -2/5 = -4/5 = c/a
Hence,
verified !
5x² - 4 - 8x is written in standard form as:-
p(x) = 5x² - 8x - 4
a = 5 , b = -8 , c = -4
sum of zeros = -b/a = -(-8)/5 = 8/5
product of zeros = c/a = -4/5
=====================================
5x² - 8x - 4 = 0
5x² - 10x + 2x - 4 = 0
5x(x - 2) + 2(x - 2) = 0
( x - 2) ( 5x + 2) = 0
x = 2
x = -2/5
The zeros are 2 and -2/5
sum of zeros = 2 + -2/5 = 10 -2/5 = 8/5 = -b/a
product of zeros = 2 × -2/5 = -4/5 = c/a
Hence,
verified !
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