Find zeros of quadratic polynomial and verify the relation between the zeros and coefficient 3×2-×-4
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Answered by
1
Answer:
Let f(x)=4x
2
−4x−3
=4x
2
−(6x−2x)−3
=4x
2
−6x+2x−3
=2x(2x−3)+1(2x−3)
=(2x+1)(2x−3)
To find the zeroes, Let f(x)=0
(2x+1)(2x−3)=0
2x+1=0 or 2x−3=0
again
sum of zeroes =
2
−1
+
2
3
=
2
(−1+3)
=
2
2
=
a
−b
=
(coefficient of x
2
)
(−coefficient of x)
Product of zeroes =
2
−1
×
2
3
=
4
(−3)
=
a
c
=
coefficient of x
2
constant term
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3
Answer:
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