find zeros of root 3x esquire - 8 x + 4 root 3
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3x2 -8x+4root3 = 3x2-6x-2x+4root3 = 3x(x-2root3)-2(x- 2root3)=(3x-2)(x-2root3)
- zeroes = x=2/3,x= 2root3
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the zeroes are 2 root 3 , 2/root 3
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