Question

find zeros of the following polynomial 3x²+8x+4​

Answer 1

Answer:

ZERO OF THE POLYNOMIAL ARE

x = -4

x = - 2 / 3

Step-by-step explanation:

$3 {x}^{2} + 8x + 4 = 3 {x}^{2} + 6x + 2x + 4 \\ \\ = 3x(x + 2) + 2(x + 4) \\ \\ = (3x + 2)(x + 4)$

X = -4 or x = - 2 / 3

Answer 2

$\: \: \: \: \: \: \: \: \: \: \: \: \:\: \sf{3 {x}^{2} + 8x + 4 = 0}$

$: ⟹ \: \sf { 3 {x}^{2} + 6x + 2x + 4 = 0}$

$: ⟹ \: \sf{ 3x(x + 2) + 2(x + 2) = 0}$

$: ⟹ \: \: \: \: \: \sf{(x + 2)(3x + 2) = 0}$

$: ⟹ \: \sf{x + 2 = 0 \: and \: 3x + 2 = 0}$

$: ⟹ \: \: \: \: \red{\boxed { \sf{ x\: = - 2 \: and \: - \frac{2}{3} }}}$