Question

find zeros of the following quadratic polynomial 4y square + 8y​

Answer 1

Answer:

4y sqaure = 8y so , 8y -8y = 0

Step-by-step explanation:

sorryy bro i am class 7 so idnt know that.

Answer 2

Answer:

0 and -2 are the zeroes of the given quadratic  polynomial.

Step-by-step explanation:

Explanation:

Given in the question that,$4y^2 + 8y$.

• Quadratic Polynomial - A quadratic polynomial is one that has the form a$x^2$+bx + c, where a, b, and c are real numbers and a ≠ 0.

• Zeroes of a quadratic polynomial, each and every quadratic polynomial has two zeros.

• The values of the variable for which the polynomial as a whole has 0 value are known as the polynomial's zeros.

Step 1:

From the question we have $4y^2 + 8y$.

⇒$4y^2 + 8y$ =0

⇒ 4y (y + 2)=0

So, the zeroes of the given polynomial are,

4y = 0  and(y + 2) = 0

⇒y = 0 and y = -2.

Final answer:

Hence, 0 and -2 are the zeroes of the given quadratic polynomial.

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