Question

find zeros of the following quadratic polynomials and verify the relationship between the zeros and the cofficients x square + 7x + 12 =0​

Answer 1

Answer:

(x+3)(x+4)

zeros are -3 and -4

Step-by-step explanation:

x²+7x+12 12=4x3 7=4+3

=x²+4x+3x+12

=(x²+4x)+(3x+12)

=x(x+4)+3(x+4)

=(x+3)(x+4)

Answer 2

Answer:

-3,-4

Step-by-step explanation:

x^2+3x+4x+12

x(x+3)+4(x+3)

(x+4)(x+3)=0

so the value of x can either be -4 or -3 as one of them should be 0.

coefficient of x square=1

1-4

or

1-5

is the relation