find zeros of the given polynomial. plzzzz say me fast.
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1
Answer:
p(x)= x^2+ 2x + 3x+ 6
p(x) = x( x+2 ) + 3 (x+2)
p(x)= (x+3) (x+2)
so the roots are -
x+3=0
x= -3
x+2=0
x= -2
so -2,-3 are the two roots of x^2+5x+6
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Answered by
2
Answer:
x square+ 5 x + 6 is 0
x square+ 2x+3x+6 is 0
x(x+2) 3(x+2)
x is -2 or -3
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