Question

find zeros of the polynomial 2x square -25 ?

Answer 1

given equation :-

2x² - 25

( √2x )² - ( 5 )²

Using identity :- a² - b² = ( a + b ) ( a - b )

( √2x + 5 ) ( √2x - 5 )


• ( √2x + 5 ) = 0

x = - 5 /√2

• ( √2x - 5 ) = 0

x = 5 /√2

Answer 2

Answer:

The Zeros of the polynomial is  

$x=-\frac{5}{\sqrt{2}},\frac{5}{\sqrt{2}}$

Step-by-step explanation:

Given : Polynomial $2x^2-25$

To find : The zeros of the polynomial?

Solution :

Polynomial $2x^2-25=0$

Applying identity,

$a^2 - b^2 = ( a + b ) ( a - b )$

$(\sqrt{2}x)^2-(5)^2=0$

$(\sqrt{2}x+5)(\sqrt{2}x-5)=0$

Either  $(\sqrt{2}x+5)=0$

$\sqrt{2}x=-5$  

$x=-\frac{5}{\sqrt{2}}$

Or

$(\sqrt{2}x-5)=0$

$\sqrt{2}x=5$

$x=\frac{5}{\sqrt{2}}$

The Zeros of the polynomial is  

$x=-\frac{5}{\sqrt{2}},\frac{5}{\sqrt{2}}$