Find zeros of the polynomial fx equal to 4 root 3 x square + 5 x minus 2 root 3
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ok so the Equation in the question is
4√3*x^2 + 5*x - 2√3 = 0
simply apply the formula to find roots of quadratic equation
you will get
roots = (-5 + √121)/2 and (-5 - √121)/2
as your roots
121 = 11^2
so the answer becomes
(-5+11)/2 = 3 and (-5-11)/2 = -8
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