find zeros of the polynomial p(x)= (x-2)^2-(x+2)^2
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Step-by-step explanation:
Given:
p(x) = (x - 2)² - (x + 2)²
To find:
zeroes of the polynomial.
Solution:
We have
p(x) = (x - 2)² - (x + 2)²
Finding a zero of the polynomial, is the same as solving the equation p(x) = 0, we get
(x - 2 + x + 2)(x - 2 - x - 2) = 0
⇒ (2x) (-4) = 0
⇒-8x = 0
⇒x = 0
Hence, 0 is a zero of the polynomial p(x) = (x - 2)² - (x + 2)²
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