Question

Find zeros of the polynomial p(x)=(x-4)^2-(x-6)^2​

Answer 1

$p(x) = x {}^{2} - 8x + 16 - x {}^{2} - 12x + 36 \\ p(x) = - 20x + 56 \\ 0 = - 20x + 56 \\ 20x = 56 \\ x = \frac{56}{20 } \\ x = \frac{28}{10 } \\ x = \frac{14}{5 } \\ x = 2.8$

Answer 2

Step-by-step explanation:

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