Question

Find zeros of
the polynomial
$\sqrt{3x {}^{2} } - 8x + 4 \sqrt{3}$
​

Answer 1

Given Polynomial : √3x² - 8x + 4√3

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Need to find : The Zeroes of the given polynomial.

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$\:\:$❭❭ Finding out the zeroes of Given polynomial :

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$\:\:\:\:\:\:\:\:\::\:\Longrightarrow\:{\sf{\sqrt{3}}x^{2}\:-\:8x\:+\:4\sqrt{3}}$

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$\:\:\:\:\:\:\:\:\:\::\:\Longrightarrow\:{\sf{\sqrt{3}}x^{2}\:-\:8x\:+\:4\sqrt{3}\:=\:0}$

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$\:\:\:\:\:\::\:\Longrightarrow\:{\sf{\sqrt{3}}x^{2}\:-\:2x\:-\:6x\:+\:4\sqrt{3}}$

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$\:\:\:\:\:\:\:\:\::\:\Longrightarrow\:{\sf{(\:\sqrt{3}x\:-\:2\:)\:(\:x\:-\:2\sqrt{3}\:)}}$

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$\:\:\::\:\Longrightarrow\:{\underline{\boxed{\frak{\blue{x\:=\:{\dfrac{2}{\sqrt{3}}}\:or\:x\:=\:2\sqrt{3}}}}}}\:\bigstar$

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$\:\therefore\:{\underline{\sf{Hence,\:the\:zeroes\:of\:the\:given\:polynomial\:are\:{\sf{\bf{\dfrac{2}{\sqrt{3}}\:or\:2\sqrt{3}}}}}}}.$

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$\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━$

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