find zeros of the polynomial x square - 25
Answers
Answered by
5
x^2 - 25 = 0
→ x = ±√25
→ x = ±5
the zeroes are +5 and -5
Answered by
2
Answer:
given:-
(x)^2-(25)^2
This is forming the formula
a^2-b^2=(a+b)(a-b)
putting values:-
(x+5)(x-5)=0
x=-5
x=5
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