FIND ZEROS OF THE POLYNOMIAL
X(X+4)=12
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Answer:
X(X+4)=12
x² + 4x - 12 = 0
x² + (6x - 2x) - 12 = 0
x² + 6x - 2x - 12 = 0
x(x+6) - 2(x+6) = 0
(x+6)(x-2) = 0
zeroes are -6, 2
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