find zeros of the polynomial x2 - (√2+1) x +√2
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Answered by
2
Answer:
=> x² - (√2+1)x + √2=0
=> x² - √2x - x+ √2=0
=> x(x - 1) -1(x- √2)
=> (x - 1) (x - √2)
=> x = 1 and, x = √2
Answered by
0
Answer:
1 and √2
Step-by-step explanation:
x^2-(√2+1)x+√2
= x^2-√2 x- x+√2
=x(x-√2)-1(x-√2)
=(x-√2)(x-1)
hence,
x=1 and√2
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