find zeros of the polynomial z^2-8
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p(x)=z²+0z-8
z²+0z-8=0
z²+2√2z-2√2z-8=0
z(z+2√2)-2√2(z+2√2)=0
(z-2√2)(z+2√2)=0
z-2√2=0
=>z=2√2
z+2√2=0
=>z=-2√2
z=2√2,-2√2
hope it helps you....
z²+0z-8=0
z²+2√2z-2√2z-8=0
z(z+2√2)-2√2(z+2√2)=0
(z-2√2)(z+2√2)=0
z-2√2=0
=>z=2√2
z+2√2=0
=>z=-2√2
z=2√2,-2√2
hope it helps you....
komalprajapat:
iska answer root me aa rha h
bookback ans root me kya hai??
root 8 , -root 8
sry dear...
its okk
now go check the ans...it would be correct .
noo
aare baba...
√8=√2*√2*√2=2√2
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