Question

Find zeros of the quadratic equation x²- 7x + 12

Answer 1

${x}^{2} - 7x + 12 = 0 \\ \\ {x}^{2} - 4x - 3x + 12 = 0 \\ \\ x(x - 4) - 3(x - 4) \\ \\ (x - 4)(x - 3) \\ \\ x = 4 \: or \: x = 3$

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Answer 2

Answer:

find the zeroes by the factorisation method

Step-by-step explanation:

= x2 -7x +12

=x2 - 4x - 3x + 12

= x(x-3) -4(x-3)

= (x-3)(x-4)

= x = 3

= x = 4