Question

find zeros of the quadratic polynomial 6x²-3-7x.​

Answer 1

Answer:

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Answer 2

Answer:

6x²−3−7x=6x²−7x−3=0

⇒6x²+2x−9x−3=0

⇒2x(3x+1)−3(3x+1)=0

⇒(2x−3)(3x+1)=0

Zeros = 3/2 , -1/3

α+β= -b/a ⇒ 3/2 - 1/3 = 7/6 = (-7)/6 = -b/a

αβ= c/a ⇒(3/2) (1/3) = -1/2 = -3/6 = c/a

Step-by-step explanation:

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