Question

find zeros of the quadratic polynomial x^2+2√3x-9 ​

Answer 1

Answer:

p(x)=x²+2√3x-9

p(0)= x²+2√3x-9 =0

= x² -√3x+3√3x -9=0

= x(x-√3) +3√3(x-√3)=0

= x+3√3=0 or x-√3=0

x=-3√3. or x= √3