Question

find zeros of x^2-5x+4 ​

Answer 1

Answer:

Step-by-step explanation:

X2-4x-x+4

= x(x-4) - 1(x-4)

= (x-1)(x-4)

Answer 2

Hey mate here is your answer....

x^2 - 5x + 4 = 0

x^2 - 4x - x + 4 = 0

x (x - 4) - 1 (x - 4) = 0

(x - 4) (x - 1) = 0

(x - 4) = 0, (x-1) = 0

x = 4 , x = 1

So, 1 and 4 are the zeroes of x^2 -5x + 4

Hope it help you... So, Plzz mark my ans as brainliest answer....