Math, asked by itsmepradyumn, 9 months ago

find zeros of x^3-2/3x^2+6x+9​

Answers

Answered by vishal25505
1

Step-by-step explanation:

2x3-3x2+6x-9=0

Three solutions were found :

x = 3/2 = 1.500

x= 0.0000 - 1.7321 i

x= 0.0000 + 1.7321 i

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((2 • (x3)) - 3x2) + 6x) - 9 = 0

Step 2 :

Equation at the end of step 2 :

((2x3 - 3x2) + 6x) - 9 = 0

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