Question

find zeros of x^3-8x^2+5x-81​

Answer 1

Step-by-step explanation:

Given  

find zeros of x^3-8x^2+5x+ 50

Given question is x^3 – 8 x^2 + 5 x + 50

So if we take x = - 2 we see that

f (x) = 0

So the equation is divisible by x – 2

So x + 2) x^3 – 8 x^2 + 5 x + 50(x^2 – 10 x  + 25

              X^3 + 2 x^2  

     ---------------------------------------------

                         -10 x^2 + 5 x  

                          -10 x^2 – 20 x

       -------------------------------------------------

                                         25 x + 50

                                          25 x + 50

             ------------------------------------------------------

                                                  0

So we get factors as (x + 2) (x^2 – 10 x + 25)

                (x + 2)(x – 5)^2