find zeros of -x^3+x-1
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zeroes of - x^3+x-1 is
alpha + beta + gamma = -b/a
a=-1
b=0
c=1
d=-1
-b/a
=0/-1
=0
aplha beta + beta gamma + gamma alpha = c/a
=1/-1
=-1
alpha × beta × gamma = -d/a
=-1/-1
=1
so zeroes of polynomial is 0, -1, 1
alpha + beta + gamma = -b/a
a=-1
b=0
c=1
d=-1
-b/a
=0/-1
=0
aplha beta + beta gamma + gamma alpha = c/a
=1/-1
=-1
alpha × beta × gamma = -d/a
=-1/-1
=1
so zeroes of polynomial is 0, -1, 1
nancy60:
it's correct or not
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