Question

Find zeros of x(x-1)(x+2)​

Answer 1

Step-by-step explanation:

$x {}^{2} - x \times x {}^{2} + 2x \\ = 2x {}^{2} - x \\ = 2x {}^{2} = x \\ = 2 = x \div x {}^{2} \\ = 2 = 1 \div x \\ = 2 \div 1 = 1 \div x \\ = 2x = 1 \\ = x = \\ + - 1 \div 2 \\ hope \: itz \: the \: answer$

Answer 2

Step-by-step explanation:

That guys right ma dear