find zeros p(x)=X²-5x+4
Answers
Given:
p(x) = x² - 5x + 4
To find:
The zeroes of p(x).
Solution:
First,
To check that p(x) = x² - 5x + 4 has real roots,
a = 1, b = -5, c = 4
b² - 4ac
(-5)² - 4 * 1 * 4
25 - 16
9
Since, 9 > 0, p(x) has 2 real roots.
Now,
We know that:
-b ± √ b² - 4ac / 2a tto find zeroes of a given polynomial p(x)
-(-5) ± √ (-5)² - 4 * 1 * 4 / 2 * 1
5 ± √ 25 - 16 / 2
5 ± √9 / 2
5 ± 3 / 2
5 + 3 / 2 and 5 - 3 / 2
8 / 2 and 2 / 2
4 and 1 are the zeroes of p(x).
Conclusion:
Therefore, the roots of p(x) = x² - 5x + 4 are 4 and 1.
Verification:
p(x) = x² - 5x + 4
p(1) = 1² - 5 * 1 + 4
p(1) = 1 - 5 + 4
p(1) = 5 - 5
p(1) = 0
p(4) = 4² - 5 * 4 + 4
p(4) = 16 - 20 + 4
p(4) = 20 - 20
p(4) = 0
Since, p(1) = 0 and p(4) = 0.
Therefore, 1 and 4 are the zeroes of p(x) = x² - 5x + 4.
Extra Information:
To find the zeroes of a quadratic polynomial we use,
-b ± √ b² - 4ac / 2a
To check whether a quadratic polynomial has zeroes we can check by the following ones,
b² - 4ac > 0, it has 2 real zeroes
b² - 4ac = 0, it has equal zeroes
b² - 4ac < 0, it has no real zeroes
Given:
p(x) = x² - 5x + 4
To find:
The zeroes of p(x).
Solution:
First,
To check that p(x) = x² - 5x + 4 has real roots,
a = 1, b = -5, c = 4
b² - 4ac
(-5)² - 4 * 1 * 4
25 - 16
9
Since, 9 > 0, p(x) has 2 real roots.
Now,
We know that:
-b ± √ b² - 4ac / 2a tto find zeroes of a given polynomial p(x)
-(-5) ± √ (-5)² - 4 * 1 * 4 / 2 * 1
5 ± √ 25 - 16 / 2
5 ± √9 / 2
5 ± 3 / 2
5 + 3 / 2 and 5 - 3 / 2
8 / 2 and 2 / 2
4 and 1 are the zeroes of p(x).
Conclusion:
Therefore, the roots of p(x) = x² - 5x + 4 are 4 and 1.
Verification:
p(x) = x² - 5x + 4
p(1) = 1² - 5 * 1 + 4
p(1) = 1 - 5 + 4
p(1) = 5 - 5
p(1) = 0
p(4) = 4² - 5 * 4 + 4
p(4) = 16 - 20 + 4
p(4) = 20 - 20
p(4) = 0
Since, p(1) = 0 and p(4) = 0.
Therefore, 1 and 4 are the zeroes of p(x) = x² - 5x + 4.
Know more :
To find the zeroes of a quadratic polynomial we use,
-b ± √ b² - 4ac / 2a
To check whether a quadratic polynomial has zeroes we can check by the following ones,
b² - 4ac > 0, it has 2 real zeroes
b² - 4ac = 0, it has equal zeroes
b² - 4ac < 0, it has no real zeroes