find zeros pf polynomial x^2+x-p(p+1)
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Answer :
Now,
x² + x - p (p + 1)
= x² + x - p² - p
= (x² - p²) + (x - p)
= (x + p) (x - p) + (x - p)
= (x - p) (x + p + 1)
So, the required zeroes of the given polynomial are
x = p, (- p - 1)
#MarkAsBrainliest
Now,
x² + x - p (p + 1)
= x² + x - p² - p
= (x² - p²) + (x - p)
= (x + p) (x - p) + (x - p)
= (x - p) (x + p + 1)
So, the required zeroes of the given polynomial are
x = p, (- p - 1)
#MarkAsBrainliest
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