Question

find zerosof the polynomial
$x2 - 2x - 8$
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Answer 1

$\bf\purple{\underline{\boxed{Question}}}$

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$\small\tt{x^{2}-2x-8}$

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$\bf\purple{\underline{\boxed{Solution}}}$

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✏

$\small\tt{x^{2}-2x-8}$

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$\small\tt{Let's\: factorise\: this\: equation}$

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$\small\tt{We\:will\:get,}$

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$\small\tt{x^{2}-4x+2x-8=0}$

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$\small\tt{x(x-4)+2(x-4)}$

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$\small\tt{(x+2)\:(x-4)=0}$

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$\small\tt{Therefore,}$

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$\small\tt{x={-2}{4}}$

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$\small\tt{The \:zeroes\:of\:f(x)\:are\:-2\:and\: 4.}$

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$\small\tt{Now\:for\:finding\:the\:zeroes\:of \:the\: }$ $\tt{polynomial.}$

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$\small\tt{We\: use,}$

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$\small\tt{ \boxed{Sum\:of\:the\:zeroes=\alpha+ \beta}}$

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$\tt\red{-2+4\:=\:2}$

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$\small\tt{ \boxed{Product\:of\:the\:zeroes=α \times β}}$

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$\tt\red{-2\times(4)=-8}$

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$\bf\purple{\underline{\boxed{Thanks}}}$

Answer 2

Answer:

answer to your question is in the following pic

Step-by-step explanation:

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