Question

find zroes of the polynomial 2x²+3x-6​

Answer 1

Answer: (9 ± √57)/4

Step-by-step explanation:

2x² + 3x - 6

This cannot be factorised by splitting the middle term .

Hence by Sridhar acharya's Formula , for ax² + bx + c = 0 we get the 2 roots :-

$\frac{- b + \sqrt{b^2 - 4ac}}{2a}$  and $\frac{-b - \sqrt{b^2 - 4ac} }{2a}$

In this case , a = 2 ,  b = 3 , c = -6

So  $\frac{-3 + \sqrt{3^2 - 4*2*(-6)} }{4} and \frac{-3 - \sqrt{3^2 -4*2*(-6)} }{4}$

=> (9 + √(9 + 48)/4 and (9 - √(9 + 48)/4

=> (9 ± √57)/4

So these are the roots .

Hope this helps you.

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