Find2 numbers whose sum is 90 and their defferance is 12
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Answered by
0
let the now be X and y
X+y=90
x-y=12
2x=102
X==51
y=49
X+y=90
x-y=12
2x=102
X==51
y=49
pranav4600:
you r wrong
Answered by
0
let first no. be x
second be y
a/q
x+y=90
x-y=12
using substitution method
90-y-y=12
90-2y=12
2y=78
y=39
so,
x=51
second be y
a/q
x+y=90
x-y=12
using substitution method
90-y-y=12
90-2y=12
2y=78
y=39
so,
x=51
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