Question

finda number such that if 5,15,and 35 are added to it, the product of the first and third results may be equal to the square of the second?

Answer 1

Let the number be 'x'
By the problem,
(x+5)(x+35)=(x+15)²
x²+40x+175=x²+225+30x
10x=225-175
x=50/10
x=5
Therefore the number is 5.

Answer 2

let the no. be x
now according to the question
(x+5)(x+35) = (x+15)^2
x^2+40x+175 = x^2+30x+225
10x = 50
x = 5
therefore the required no. is 5

hope this helps:p