Question

findcthe area of a wall shown in figure

Answer 1

Length of wall = 100m
Hight of wall excluding hight of trangulated portion = 60m
area = (length )(breadth)
area = 100 multiplied by 60
area= 6000 m sq. - (1)

Hight of trangulated portion of wall = 15 m
area of trangle = 1/2 multiplied by base multiplied by hight
area of trangulated portion = 1/2(100)(15)
=(50)(15)
=750 m sq. -(2)
Total area of wall = area-(1) +area-(2)
=6000 + 750
= 6750 m sq
ANS

Answer 2

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