finddy÷dx. y=log(sin(4x-3))
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Given,
- y=log(sin(4x-3))
To find,
- We have to find dy/dx.
Solution,
We can simply find dy/dx by differentiating y with respect to x.
It is given that y = log(sin(4x-3))
Now, differentiate both sides with respect to x, we get
d(y)/dx = d(log(sin(4x-3))/dx
As we know that d(logx)/dx = 1/x, d(sinx)/dx = cosx , d(4x)/dx = 4 then
dy/dx = 1/ (sin(4x-3)) * (cos(4x-3) * (4)
dy/dx = cos(4x-3)/sin (4x-3) * 4
As we know that cosx/sinx = cotx, then
dy/dx = 4 cot(4x-3)
Hence, the value of dy/dx if y= log(sin(4x-3)) is 4 cot(4x-3).
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