Question

Finde the y if the distance between a=(2, -3) and b=(-1, y) is 5 unit
IF YOU TOLD CORRECT I WILL MARK YOU AS BRAIN LIST​

Answer 1

Answer:

- 7 and 1

Step-by-step explanation:

A( $x_{1}$ , $y_{1}$ )

B( $x_{2}$ , $y_{2}$ )

d = $\sqrt{(x_{2} -x_{1} )^2 + (y_{2} -y_{1} )^2}$

~~~~~~~~~~~

A(2, - 3)

B( - 1, y)

$\sqrt{(-1-2)^2 +(y-(-3))^2 }$ = 5

( $\sqrt{9+(y+3)^2}$ )² = 5²

9 + (y + 3)² = 25

9 + y² + 6y + 9 - 25 = 0

y² + 6y - 7 = 0

D = b² - 4ac = (6)² - 4(1)( - 7) = 64 = 8²

$y_{1}$ = $\frac{-b+\sqrt{D} }{2a}$ = $\frac{-6+8}{2}$ = 1

$y_{2}$ = $\frac{-b-\sqrt{D} }{2a}$ = $\frac{-6-8}{2}$ = - 7

y ∈ { - 7, 1 }

Answer 2

Question : Finde the y if the distance between a=(2, -3) and b=(-1, y) is 5 unit

Answer:

A

(

5

,

−

9

)

B

(

11

,

y

)

A

B

=

10

=

10

=

√

(

11

−

5

)

2

+

(

y

+

9

)

2

squaring on both sides

100

=

(

6

)

2

+

(

y

+

9

)

2

100

=

36

+

(

y

+

9

)

2

|

y

+

9

|

=

√

64

y

+

9

=

8

,

y

+

9

=

−

8

y

=

−

1

,

y

=

−

17

y

Step-by-step explanation:

Hope this answer will help you.