findHCF of 72 and96 by Euclid division lemma and express it in the form 96m +72n
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Here we need to find the HCF of 2 Number ie: 72 & 96 by Euclid's Division algorithm .
So , here 72 < 96 therefore by using Euclid's Division algorithm ( a = b × q + r )
We have
96 = 72 × 1 + 24 --- eq (1 )
( Dividend = 96 , Quotient = 1 , Divisor = 72 & Remainder = 24 )
-- Now taking the obtained divisor as dividend and remainder as divisor we have ---
72 = 24 × 3 + 0
Therefore
Now ATQ we need to convert 24 into 96m - 72n form
So from Equation 1 we have
24 = 96 -72 × 1
thus it's the required form 24 = 96m + 72n where m = 1 & n = -1
Euclid's Division lemma
Given two positive integer a & b there exits unique integer q and r which satisfies
a = bq + r
where r ≥ 0 but less than b .
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