Finding a Missing Polynomial Addend The sum of two polynomials is 10a2b2 – 8a2b + 6ab2 – 4ab + 2. If one addend is –5a2b2 + 12a2b – 5, what is the other addend?
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Answer:
15a²b² – 20a²b + 6ab² – 4ab + 7
Step-by-step explanation:
Let the other addend be 'A'.
– 5a²b² + 12a²b – 5 + A = 10a²b² – 8a²b + 6ab² – 4ab + 2
A = 10a²b² – 8a²b + 6ab² – 4ab + 2 - (– 5a²b² + 12a²b – 5 )
A = 10a²b² – 8a²b + 6ab² – 4ab + 2 + 5a²b² - 12a²b + 5
A = 10a²b² + 5a²b² – 8a²b - 12a²b + 6ab² – 4ab + 2 + 5
A = 15a²b² – 20a²b + 6ab² – 4ab + 7
So, the other addend is 15a²b² – 20a²b + 6ab² – 4ab + 7
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