Question

Finding a quadratic polynomials with zeores 2 and1/2

Answer 1

Answer:

2x2-5+2

Step-by-step explanation:

Let a=2 and b=1/2

a+b=2+1/2 ab=2×1/2

=5/2 =1

Quadratic polynomial =x2-(a+b)x+ab

=x2-(5/2)x+1

=2x2-5+2

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2

=1/2(2x2-5+2)

Answer 2

Answer:

Step-by-step explanation:

Alpha = 2 & Beta = 1/2

alpha + beta = -b/a

2 + 1/2 = -b/a

5/2= -b/a

b = -5

a = 2

alpha X beta = c/a

2 X 1/2 = c/a

1= c/a

multiplying by 2 both the sides

2/2 = c/a

c = 2

a = 2

Hence the required polynomial is - 2x^2 - 5x + 2

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