Question

Finding sum of digits of a number until sum becomes single digit

Answer 1

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Answer 2

Answer:

#include<iostream>  

using namespace std;  

int digSum(int n)  

{  

int sum = 0;  

while(n > 0 || sum > 9)  

{  

if(n == 0)  

{  

n = sum;  

sum = 0;  

}  

sum += n % 10;  

n /= 10;  

}  

return sum;  

}  

int main()  

{  

int n;

cin>>n;

cout << digSum(n);  

return 0;  

}

Step-by-step explanation: