Question

finding the equation of a straight line y=mx+c which is perpendicular to the line 3x-4y+5=0 and passes through the point of intersection of the lines 2x+y=5 and x-y=1

Answer 1

Answer:

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Step-by-step explanation:

Equation of all lines passing through intersection of given lines is L: 3x-4y+4+k(x+y-1) =0 for different values of k. It's slope is (3+k)/(-4+k). Since L is perpendicular to x-y=0, whose slope is 1. So

(3+k)/(-4+k) *1 = -1 or or 3+k=4-k => 2k=1 or k=1/2

So reqd line is 3x-4y+4+(1/2)*(x+y-1)=0. Simplifing

7x-7y+7=0 or x-y+1=0