Question

Finding the roots using factorization method.
3p (2p-1) - 17 = (2p-5)²

Answer 1

Step-by-step explanation:

3p(2p-1)-17=4psqu.+25.-20p

6psqu.-4psu. -3p +20p +25 =0

2psu.+17p+25=0

now factorize

Answer 2

Answer:

$\green { \frac{-21}{2} \:Or \: 2}$

Step-by-step explanation:

$3p(2p-1)-17 = (2p-5)^{2}$

$\implies 6p^{2} - 3p - 17 = (2p)^{2} + 5^{2} - 2\times (2p)\times 5$

$\implies 6p^{2} - 3p - 17 = 4p^{2} + 25 - 20p$

$\implies 6p^{2} - 3p - 17 - 4p^{2} + 20p - 25 =0$

$\implies 2p^{2} + 17p - 42 = 0$

$\implies 2p^{2} +21p - 4p - 42 = 0$

$\implies p(2p+21) - 2(2p+21) = 0$

$\implies (2p+21)(p-2) = 0$

$\implies 2p+21 = 0 \: Or \: p-2 = 0$

$\implies 2p = -21 \:Or \: p = 2$

$\implies p = \frac{-21}{2} \:Or \: p = 2$

Therefore.,

$\green { \frac{-21}{2} \:Or \: 2 \: are \: roots \: of }$

$\green { quadratic \: eqution }$

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