findP(0) if P(y)=y²+y+1
Answers
Answered by
1
p = 0 then
(0)² + (0) +1
0 + 1
= 1
(0)² + (0) +1
0 + 1
= 1
Answered by
1
P(0)=0²+0+1
=0+1
=1
[P(0)=1 ] Ans
=0+1
=1
[P(0)=1 ] Ans
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