Question

Findp(-2) p(-1) p(0) in the expressionp(y)=3y^2-5y+7

Answer 1

Answer:

              p(y) = 3y^2-5y+7......eqn 1

                        putting -2 in y in eqn 1

         for,    p(-2) = 3*(-2)^2-5*-2+7 = 12+10+7 = 29...ANS

                        putting -1 in y in eqn 1

         for,     p(-1) = 3*(-1)^2-5*-1+7 =  3+10+7 = 20...ANS

                         putting 0 in y in eqn 1

         for,     p(0) = 3*0^2-5*0+7 = 0+0+7 = 7...ANS

Answer 2

Step-by-step explanation:

HERE THE PHOTO! I HAVE EXPLAINED IN THE RIGHT WAY FULLY CORRECT ANSWER!!