Question

Finds The roots of x²-10x-96 by Factorisation ​

Answer 1

Answer:

${x}^{2} - 10x - 96 \\ \\ = {x}^{2} - (16 - 6)x - 96 \\ \\ = {x}^{2} - 16x + 6x - 96 \\ \\ = x(x - 16) + 6(x - 16) \\ \\ = (x -16)(x + 6)$

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Answer 2

Answer:

x-16,x-6

is the correct answer hope you get it no explanation