Question

finds the velue 2x^2+5x+6
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Answer 1

Answer:

Step-by-step explanation:

∫dx/(2x^2 + 5x + 6) = 1/2 * ∫dx/(x^2 + 5x/2 + 3) = 1/2 * ∫dx/((x + 5/4)^2 + 23/16))  

= 8/23 * ∫dx/((4/√23 * (x + 5/4))^2 + 1)  

= 2/√23 * arctan(4/√23 * (x + 5/4)) + C